To show that the Fundamental Theorem of Algebra is true for the quadratic polynomial \(x^2 - 16x + 39 = 0\), we will solve the equation by factoring.
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Factoring the Quadratic Polynomial: We need to find two numbers that multiply to \(39\) (the constant term) and add up to \(-16\) (the coefficient of the linear term).
Looking for such pairs, we find: \[ -3 \text{ and } -13 \] because: \[ (-3) \times (-13) = 39 \] \[ (-3) + (-13) = -16 \]
Thus, we can rewrite the polynomial as: \[ (x - 3)(x - 13) = 0 \]
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Finding the Roots: Set each factor equal to zero: \[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \] \[ x - 13 = 0 \quad \Rightarrow \quad x = 13 \]
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Conclusion: The roots of the polynomial \(x^2 - 16x + 39 = 0\) are \(x = 3\) and \(x = 13\). Both of these solutions are rational numbers.
So, the statement that accurately describes the solution set is:
- There are two rational solutions.
Therefore, the correct response is: There are two rational solutions.