To solve the quadratic equation x^2 - 16x + 39 = 0, we can factor it as (x - 3)(x - 13) = 0. This implies that either (x - 3) = 0 or (x - 13) = 0.
If (x - 3) = 0, then x = 3.
If (x - 13) = 0, then x = 13.
So the solution set for the equation x^2 - 16x + 39 = 0 is {3, 13}.
Both of these solutions are rational numbers, so the accurate statement that describes the solution set is: "There are two rational solutions."
Show that the fundamental theorem of algebra is true for the quadratic polynomial x^2 - 16x + 39 = 0 through solving by factoring. which of the following statements accurately describes the solution set?
these are two irrational solutions
there are two non-real solutions
there are two rational solutions
there two identical solutions
1 answer