Asked by chris
A cyclist and a jogger start from a town at the same time and headed for a destination 24 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 3hrs ahead of the jogger. Whats the rate of the cyclist?
Answers
Answered by
PsyDAG
C = 2J (rates)
Distance = rate/time
Therefore, time = rate/distance
J/24 - C/24 = 3
Use substitution to solve first for cyclist and then for jogger.
Distance = rate/time
Therefore, time = rate/distance
J/24 - C/24 = 3
Use substitution to solve first for cyclist and then for jogger.
Answered by
Chris
is the answer 12
Answered by
PsyDAG
Sorry, I goofed!
Distance = <B>rate * time</B>
Therefore, Time = Distance/rate
24/J - 24/C = 3
Substitute 2j for C.
24/j - 24/2J = 3
Multiply both sides by J.
24 - 12 = 3J
12 = 3j
4 = J
C = 2J = 2 * 4 = 8
Sorry for the goof! This should help.
Distance = <B>rate * time</B>
Therefore, Time = Distance/rate
24/J - 24/C = 3
Substitute 2j for C.
24/j - 24/2J = 3
Multiply both sides by J.
24 - 12 = 3J
12 = 3j
4 = J
C = 2J = 2 * 4 = 8
Sorry for the goof! This should help.
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