Asked by chris

A cyclist and a jogger start from a town at the same time and headed for a destination 24 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 3hrs ahead of the jogger. Whats the rate of the cyclist?
Answered by PsyDAG
C = 2J (rates)

Distance = rate/time

Therefore, time = rate/distance

J/24 - C/24 = 3

Use substitution to solve first for cyclist and then for jogger.


Answered by Chris
is the answer 12
Answered by PsyDAG
Sorry, I goofed!

Distance = <B>rate * time</B>

Therefore, Time = Distance/rate

24/J - 24/C = 3

Substitute 2j for C.

24/j - 24/2J = 3

Multiply both sides by J.

24 - 12 = 3J

12 = 3j

4 = J

C = 2J = 2 * 4 = 8

Sorry for the goof! This should help.
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