Question

Find the difference
(3 - 2x + 2x^2) - (4x -5 +3x^2)

Answer 1

To find the difference \((3 - 2x + 2x^2) - (4x - 5 + 3x^2)\), we first distribute the negative sign across the second expression:

\[
(3 - 2x + 2x^2) - (4x - 5 + 3x^2) = 3 - 2x + 2x^2 - 4x + 5 - 3x^2
\]

Next, we combine like terms.

1. The constant terms: \(3 + 5 = 8\).
2. The \(x\) terms: \(-2x - 4x = -6x\).
3. The \(x^2\) terms: \(2x^2 - 3x^2 = -1x^2\) (or simply \(-x^2\)).

Putting it all together, we get:

\[
8 - 6x - x^2
\]

Thus, the final result for the difference is:

\[
-x^2 - 6x + 8
\]

If you would like to write it in standard form, it can be presented as:

\[
-x^2 - 6x + 8 = -1x^2 - 6x + 8
\]

Or simply:

\[
-x^2 - 6x + 8
\]