Question

A)Find the 1st difference given the second and third term. Second term is 3a+5; third term is 8a−3.(1 point)

The 1st difference is ''blank''.


answer the blank spot.

Answer 1

To find the 1st difference given the second term and third term of a sequence, we can use the formula for the 1st difference, which is calculated as:

\[
\text{1st difference} = \text{third term} - \text{second term}
\]

Given the second term as \(3a + 5\) and the third term as \(8a - 3\), we can calculate as follows:

\[
\text{1st difference} = (8a - 3) - (3a + 5)
\]

Now, simplify the expression:

\[
\text{1st difference} = 8a - 3 - 3a - 5
\]

Combining like terms:

\[
\text{1st difference} = (8a - 3a) + (-3 - 5) = 5a - 8
\]

So, the 1st difference is:

\[
\text{1st difference} = 5a - 8
\]

The blank spot can be filled with \(5a - 8\).