Question

Distribute 3, left parenthesis, 2, plus, 3, x, right parenthesis, .3(2+3x)

Answer 1

Distribute minus, 8, left parenthesis, 2, x, plus, 3, right parenthesis, .−8(2x+3)

Answer 2

Distribute minus, x, left parenthesis, minus, x, plus, 9, right parenthesis, .−x(−x+9)

Answer 3

5x(2+3x)

Answer 4

Distribute minus, 2, left parenthesis, minus, 2, x, minus, x, squared, right parenthesis, .−2(−2x−x
2
)

Answer 5

Perform the operation.
left parenthesis, 3, x, squared, minus, 3, x, plus, 9, right parenthesis, plus, left parenthesis, minus, 5, x, squared, minus, 8, x, minus, 7, right parenthesis
(3x
2
−3x+9)+(−5x
2
−8x−7)

Answer 6

To distribute \( 3(2 + 3x) \), you'll multiply each term inside the parentheses by \( 3 \).

Here's how the distribution works step by step:

1. Start with the expression:
\[
3(2 + 3x)
\]

2. Distribute \( 3 \) to each term inside the parentheses:
\[
3 \cdot 2 + 3 \cdot 3x
\]

3. Calculate each multiplication:
\[
6 + 9x
\]

Putting it all together, the expression simplifies to:
\[
6 + 9x
\]

So, \( 3(2 + 3x) = 6 + 9x \).

Answer 7

To distribute \(-8(2x + 3)\), you'll multiply \(-8\) by each term inside the parentheses.

Here’s how the distribution works step by step:

1. Start with the expression:
\[
-8(2x + 3)
\]

2. Distribute \(-8\) to each term inside the parentheses:
\[
-8 \cdot 2x + -8 \cdot 3
\]

3. Perform the multiplication:
\[
-16x - 24
\]

Putting it all together, the expression simplifies to:
\[
-16x - 24
\]

So, \(-8(2x + 3) = -16x - 24\).

Answer 8

To distribute \(-x(-x + 9)\), you'll multiply \(-x\) by each term inside the parentheses.

Here’s how the distribution works step by step:

1. Start with the expression:
\[
-x(-x + 9)
\]

2. Distribute \(-x\) to each term inside the parentheses:
\[
-x \cdot (-x) + -x \cdot 9
\]

3. Perform the multiplication:
\[
x^2 - 9x
\]

Putting it all together, the expression simplifies to:
\[
x^2 - 9x
\]

So, \(-x(-x + 9) = x^2 - 9x\).

Answer 9

To distribute \(5x(2 + 3x)\), you multiply \(5x\) by each term inside the parentheses. Here's how you can do that step by step:

1. Start with the expression:
\[
5x(2 + 3x)
\]

2. Distribute \(5x\) to each term inside the parentheses:
\[
5x \cdot 2 + 5x \cdot 3x
\]

3. Perform the multiplication:
- For the first term:
\[
5x \cdot 2 = 10x
\]
- For the second term:
\[
5x \cdot 3x = 15x^2
\]

Putting it all together, the expression simplifies to:
\[
15x^2 + 10x
\]

So, \(5x(2 + 3x) = 15x^2 + 10x\).

Answer 10

To distribute \(-2(-2x - x^2)\), you will multiply \(-2\) by each term inside the parentheses.

Here’s how it works step by step:

1. Start with the expression:
\[
-2(-2x - x^2)
\]

2. Distribute \(-2\) to each term inside the parentheses:
\[
-2 \cdot (-2x) + -2 \cdot (-x^2)
\]

3. Perform the multiplication:
- For the first term:
\[
-2 \cdot (-2x) = 4x
\]
- For the second term:
\[
-2 \cdot (-x^2) = 2x^2
\]

Putting it all together, the expression simplifies to:
\[
4x + 2x^2
\]

So, \(-2(-2x - x^2) = 2x^2 + 4x\).

Answer 11

To perform the operation \((3x^2 - 3x + 9) + (-5x^2 - 8x - 7)\), you'll combine like terms from both expressions.

Here’s how to do it step by step:

1. **Write out the expression**:
\[
(3x^2 - 3x + 9) + (-5x^2 - 8x - 7)
\]

2. **Remove the parentheses**:
\[
3x^2 - 3x + 9 - 5x^2 - 8x - 7
\]

3. **Combine like terms**:

- **For \(x^2\) terms**:
\[
3x^2 - 5x^2 = -2x^2
\]

- **For \(x\) terms**:
\[
-3x - 8x = -11x
\]

- **For constant terms**:
\[
9 - 7 = 2
\]

4. **Put it all together**:
\[
-2x^2 - 11x + 2
\]

So, the result of the operation is:
\[
\boxed{-2x^2 - 11x + 2}
\]