To simplify \((16^6)^5\), you can use the property of exponents that states \((a^m)^n = a^{m \cdot n}\).
So, applying this property:
\[ (16^6)^5 = 16^{6 \cdot 5} = 16^{30} \]
Thus, \((16^6)^5 = 16^{30}\).
Now try:
left parenthesis, 16, to the power 6 , right parenthesis, to the power 5(16
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11 answers
Now try this
(16
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(16
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It looks like you are trying to simplify \((16^6)^1\), which can be interpreted simply as:
\[ (16^6)^1 = 16^6 \]
Any number raised to the power of 1 remains the same. Thus, \((16^6)^1 = 16^6\).
Now try:
left parenthesis, 16, start superscript, one sixth, end superscript, right parenthesis, to the power 6(16
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left parenthesis, 16, start superscript, one sixth, end superscript, right parenthesis, to the power 6(16
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To simplify \(\left(16^{\frac{1}{6}}\right)^6\), you can use the exponent multiplication property, which states that \((a^m)^n = a^{m \cdot n}\).
Applying this property:
\[ \left(16^{\frac{1}{6}}\right)^6 = 16^{\frac{1}{6} \cdot 6} = 16^1 = 16 \]
So, \(\left(16^{\frac{1}{6}}\right)^6 = 16\).
Let xx = 16, start superscript, one sixth, end superscript16
6
1
. Rewrite the equation in the previous answer box, replacing 16, start superscript, one sixth, end superscript16
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with xx (substitute).
6
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. Rewrite the equation in the previous answer box, replacing 16, start superscript, one sixth, end superscript16
6
1
with xx (substitute).
Given that \( x = 16^{\frac{1}{6}} \), we can rewrite the equation from the previous answer as:
\[ \left(x\right)^6 \]
Now applying the exponent multiplication property:
\[ \left(x\right)^6 = x^{6} \]
Since \( x = 16^{\frac{1}{6}} \), we get:
\[ \left(16^{\frac{1}{6}}\right)^6 = x^6 \]
Thus, substituting back we have:
\[ x^6 = 16 \]
So, overall, we can express it as: \[ x^6 = 16 \]
Solve for a positive value of xx, expressing your answer with a radical symbol.
xx =
xx =
To solve for \( x \) in the equation \( x^6 = 16 \), you can take the sixth root of both sides:
\[ x = 16^{\frac{1}{6}} \]
Now, we can express \( 16 \) using a radical. Since \( 16 = 2^4 \), we can rewrite this as:
\[ x = (2^4)^{\frac{1}{6}} = 2^{\frac{4}{6}} = 2^{\frac{2}{3}} \]
To express \( 2^{\frac{2}{3}} \) using a radical symbol, we can write it as:
\[ x = \sqrt[3]{2^2} = \sqrt[3]{4} \]
So, the positive value of \( x \) is:
\[ x = \sqrt[3]{4} \]
3/4 is that the answer
Let's clarify the solution step:
We determined that \( x^6 = 16 \).
Taking the sixth root gives us:
\[ x = 16^{\frac{1}{6}} \]
We then expressed \( 16 \) as \( 2^4 \):
\[ x = (2^4)^{\frac{1}{6}} = 2^{\frac{4}{6}} = 2^{\frac{2}{3}} \]
To rewrite \( 2^{\frac{2}{3}} \) using radical notation:
\[ x = \sqrt[3]{2^2} = \sqrt[3]{4} \]
This is the expression we derived.
If you meant \( \frac{3}{4} \) specifically, that does not represent the value we've derived for \( x \). The solution provides \( x = \sqrt[3]{4} \), which is not equal to \( \frac{3}{4} \).
Thus, the final answer is:
\[ x = \sqrt[3]{4} \]
If you are asking if \( \frac{3}{4} \) is the value of \( x \), it is not, according to the calculations we've done. Would you like further clarification on any part of this?