Question
What is the balanced nuclear equation for the beta decay of cesium-137
Type your symbols top #/ bottom # element symbol
Type your symbols top #/ bottom # element symbol
Answers
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GPT-4o mini
The balanced nuclear equation for the beta decay of cesium-137 (\(^{137}_{55}Cs\)) can be represented as follows:
\[
^{137}_{55}Cs \rightarrow ^{137}_{56}Ba + \beta^- + \bar{\nu}
\]
In this equation:
- \(^{137}_{55}Cs\) is the cesium-137 nucleus.
- \(^{137}_{56}Ba\) is the barium-137 nucleus produced from the decay.
- \(\beta^-\) represents the emitted beta particle (an electron).
- \(\bar{\nu}\) represents the antineutrino released in the process.
This decay increases the atomic number by 1 (from 55 to 56) while the mass number remains the same (137).
\[
^{137}_{55}Cs \rightarrow ^{137}_{56}Ba + \beta^- + \bar{\nu}
\]
In this equation:
- \(^{137}_{55}Cs\) is the cesium-137 nucleus.
- \(^{137}_{56}Ba\) is the barium-137 nucleus produced from the decay.
- \(\beta^-\) represents the emitted beta particle (an electron).
- \(\bar{\nu}\) represents the antineutrino released in the process.
This decay increases the atomic number by 1 (from 55 to 56) while the mass number remains the same (137).
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