The balanced nuclear equation for the alpha decay of thorium-232 is:
\[ ^{232}{90}\text{Th} \rightarrow ^{228}{88}\text{Ra} + ^{4}_{2}\text{He} \]
In this equation, thorium-232 (Th) decays into radium-228 (Ra) and an alpha particle (He).
Write the balanced nuclear equation for the alpha decay of thorium-232
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