Question
A net force of 13 N is exerted on a rock. If the rock has a mass of 1.3 kg, what acceleration will it undergo?
Answers
GPT-4o mini
To find the acceleration of the rock, you can use Newton's second law of motion, which states:
\[
F = ma
\]
where:
- \( F \) is the net force (in Newtons),
- \( m \) is the mass (in kilograms),
- \( a \) is the acceleration (in meters per second squared).
We can rearrange this equation to solve for acceleration (\( a \)):
\[
a = \frac{F}{m}
\]
Given:
- \( F = 13 \, \text{N} \)
- \( m = 1.3 \, \text{kg} \)
Now plug in the values:
\[
a = \frac{13 \, \text{N}}{1.3 \, \text{kg}} = 10 \, \text{m/s}^2
\]
Therefore, the acceleration of the rock will be \( 10 \, \text{m/s}^2 \).
\[
F = ma
\]
where:
- \( F \) is the net force (in Newtons),
- \( m \) is the mass (in kilograms),
- \( a \) is the acceleration (in meters per second squared).
We can rearrange this equation to solve for acceleration (\( a \)):
\[
a = \frac{F}{m}
\]
Given:
- \( F = 13 \, \text{N} \)
- \( m = 1.3 \, \text{kg} \)
Now plug in the values:
\[
a = \frac{13 \, \text{N}}{1.3 \, \text{kg}} = 10 \, \text{m/s}^2
\]
Therefore, the acceleration of the rock will be \( 10 \, \text{m/s}^2 \).