Asked by Robert
Ok, This is the question:
The attendance at a baseball game was 400 people. Student Ticket cost $2 and adult tickets cost were $3. Total Ticket Sales were $1050. How many tickets of each type were sold?
This is what I did:
2x+400=1050
-400=-400
-----------
2x=650
x=325
3y+400=1050
-400=-400
-----------
3y=650
y=216.6=217
Two people told me its wrong...
One said to do this:
2x + 3(400-x)=1050
I don't really know how to break this down.
And, another person said:
If S is the number of students and A is the number of adults,
S + A = 400
2S + 3A =1050
2S + 2A = 800
Subtract the last equation from the one above. That will give you what A is. S is 400 -A
I don't really understand how the person got 800.
Is it like this?
2(S+A)=400
2S+SA=800
Is this right? If so, what do I do after this? I'm really confused. Help will be greatly appreciated.
The attendance at a baseball game was 400 people. Student Ticket cost $2 and adult tickets cost were $3. Total Ticket Sales were $1050. How many tickets of each type were sold?
This is what I did:
2x+400=1050
-400=-400
-----------
2x=650
x=325
3y+400=1050
-400=-400
-----------
3y=650
y=216.6=217
Two people told me its wrong...
One said to do this:
2x + 3(400-x)=1050
I don't really know how to break this down.
And, another person said:
If S is the number of students and A is the number of adults,
S + A = 400
2S + 3A =1050
2S + 2A = 800
Subtract the last equation from the one above. That will give you what A is. S is 400 -A
I don't really understand how the person got 800.
Is it like this?
2(S+A)=400
2S+SA=800
Is this right? If so, what do I do after this? I'm really confused. Help will be greatly appreciated.
Answers
Answered by
Patrick
S=150 and A=250
S+A=400
A=400-S
2S+3(400-S)=1050
Solve for S
S=150
Plug back in top equation
A=250
S+A=400
A=400-S
2S+3(400-S)=1050
Solve for S
S=150
Plug back in top equation
A=250
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