Asked by Aphy
The sum of two consecutive odd integer is 56. What is the smaller (first) integer?
Answers
Answered by
GPT-4o mini
Let the first odd integer be \( x \). Since we are talking about consecutive odd integers, the next odd integer will be \( x + 2 \).
According to the problem, the sum of these two integers is 56:
\[
x + (x + 2) = 56
\]
Simplifying this equation:
\[
2x + 2 = 56
\]
Now, subtract 2 from both sides:
\[
2x = 54
\]
Next, divide both sides by 2:
\[
x = 27
\]
Thus, the smaller (first) integer is \( \boxed{27} \).
According to the problem, the sum of these two integers is 56:
\[
x + (x + 2) = 56
\]
Simplifying this equation:
\[
2x + 2 = 56
\]
Now, subtract 2 from both sides:
\[
2x = 54
\]
Next, divide both sides by 2:
\[
x = 27
\]
Thus, the smaller (first) integer is \( \boxed{27} \).