A water tank in the shape of a cone has a diameter of 12 feet and a height of 15 feet. What volume of water, in cubic feet, can the tank hold? Round your answer to the nearest tenth and use 3.14 for π

To find the volume of a cone, you can use the formula:

\[ V = \frac{1}{3} \pi r^2 h \]

where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height of the cone.

Given:

• The diameter of the cone is 12 feet, so the radius \( r \) is half of the diameter:

\[ r = \frac{12}{2} = 6 \text{ feet} \]

• The height \( h \) is 15 feet.

Now, plugging these values into the volume formula:

\[ V = \frac{1}{3} \times 3.14 \times (6^2) \times 15 \]

Calculating \( (6^2) \):

\[ 6^2 = 36 \]

Now substitute back into the formula:

\[ V = \frac{1}{3} \times 3.14 \times 36 \times 15 \]

Calculating \( 36 \times 15 \):

\[ 36 \times 15 = 540 \]

Substituting again, we have:

\[ V = \frac{1}{3} \times 3.14 \times 540 \]

Calculating \( 3.14 \times 540 \):

\[ 3.14 \times 540 = 1695.6 \]

Now, divide by 3:

\[ V = \frac{1695.6}{3} = 565.2 \]

Rounding to the nearest tenth, the volume of the water tank is:

\[ \boxed{565.2} \text{ cubic feet} \]