Question

Which correctly shows the area formula for a trapezoid, A=1/2h(b1+b2) , rearranged for the quantity of interest h?(1 point) Responses h=2Ab1+b2 h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction b1=2Ah−b2 b subscript 1 baseline dequals Start Fraction 2 upper A over h End Fraction minus b subscript 2 baseline h=12A(b1+b2) h equals Start Fraction 1 over 2 End Fraction upper A left parenthesis b subscript 1 baseline plus b subscript 2 baseline right parenthesis h=b1+b22A

Answer 1

To rearrange the area formula for a trapezoid \( A = \frac{1}{2}h(b_1 + b_2) \) to solve for \( h \), follow these steps:

1. Start with the formula:
\[
A = \frac{1}{2} h (b_1 + b_2)
\]

2. Multiply both sides by 2 to eliminate the fraction:
\[
2A = h (b_1 + b_2)
\]

3. Divide both sides by \( (b_1 + b_2) \) to isolate \( h \):
\[
h = \frac{2A}{b_1 + b_2}
\]

So the correct rearranged formula for \( h \) is:
\[
h = \frac{2A}{b_1 + b_2}
\]

This corresponds with the option "h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction."