Asked by Anonymous
derivative of (4Cos^2(3x)+3)^2
Answers
Answered by
drwls
Multiply it out and differentiate it one term at a time. Multiplication results in
16 cos^4(3x) + 24 cos^2(3x) + 9
The derivative of the last term is zero.
Let u = cos (3x) and use the function of a function "chain rule" for the other two terms
The derivative of 24 cos^2(3x) (or 24 u^2) is
48 u du/dx = 48 cos(3x)*(-sin(3x))*3
= -144 sin(3x)cos(3x) = -72 sin(6x)
I leave the other term up to you.
16 cos^4(3x) + 24 cos^2(3x) + 9
The derivative of the last term is zero.
Let u = cos (3x) and use the function of a function "chain rule" for the other two terms
The derivative of 24 cos^2(3x) (or 24 u^2) is
48 u du/dx = 48 cos(3x)*(-sin(3x))*3
= -144 sin(3x)cos(3x) = -72 sin(6x)
I leave the other term up to you.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.