Asked by hayden
sin^4cos^2x=(1/16)(1-cos 2x)(1-cos4x)
work one 1 side only!
work one 1 side only!
Answers
Answered by
Reiny
pick x=50ยบ
LS = .202..
RS = .379..
Your equation is NOT an identity
I assumed your LS = sin^x4cos^2x
you had sin^2[cos^2x], but I doubt that is what you meant.
(that would be even worse)
LS = .202..
RS = .379..
Your equation is NOT an identity
I assumed your LS = sin^x4cos^2x
you had sin^2[cos^2x], but I doubt that is what you meant.
(that would be even worse)
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