Question

JK has endpoints at J(-12,0) and K(3,-1) Find the midpoint M of JK
Write the coordinates as decimals or integers

Answer 1

To find the midpoint \( M \) of the line segment \( JK \) with endpoints \( J(-12, 0) \) and \( K(3, -1) \), we can use the midpoint formula:

\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

Where \( (x_1, y_1) \) are the coordinates of point \( J \) and \( (x_2, y_2) \) are the coordinates of point \( K \).

Substituting the coordinates:

\[
M = \left( \frac{-12 + 3}{2}, \frac{0 + (-1)}{2} \right)
\]

Calculating the x-coordinate:

\[
\frac{-12 + 3}{2} = \frac{-9}{2} = -4.5
\]

Calculating the y-coordinate:

\[
\frac{0 + (-1)}{2} = \frac{-1}{2} = -0.5
\]

Therefore, the coordinates of the midpoint \( M \) are:

\[
M(-4.5, -0.5)
\]