Asked by hydro
What net force would actually be necessary to stop an automobile of mass 880 traveling initially at a speed of 52.0 in a distance equal to the diameter of a dime, which is 1.8 ?
Answers
Answered by
Damon
You gave no units.
I will assume 880 kg
52 m/s
1.8 cm which is .018 meters
F = m a so we need a
v = Vi + a t
0 = 52 + a t
so a t = -52
a =-52/t
then
d = (1/2) a t^2
.018 = (1/2) (-52/t) t^2
t = .018/26 = 6.92 * 10^-4
so
a = -52/t = -52 /(6.922*10^-4)
then
F = 880 a
I will assume 880 kg
52 m/s
1.8 cm which is .018 meters
F = m a so we need a
v = Vi + a t
0 = 52 + a t
so a t = -52
a =-52/t
then
d = (1/2) a t^2
.018 = (1/2) (-52/t) t^2
t = .018/26 = 6.92 * 10^-4
so
a = -52/t = -52 /(6.922*10^-4)
then
F = 880 a
Answered by
drwls
This question was asked three days ago, with the proper units included.
See
http://www.jiskha.com/display.cgi?id=1268561532
See
http://www.jiskha.com/display.cgi?id=1268561532
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.