Asked by anonymous
solve for x:
1. x = (m/n)x + 2
2. x = [2/x] - [2/(2x+1)] = 1/(x+1)
I don't understand how to properly isolate X to get the value of x...please help!
1. x = (m/n)x + 2
2. x = [2/x] - [2/(2x+1)] = 1/(x+1)
I don't understand how to properly isolate X to get the value of x...please help!
Answers
Answered by
drwls
1. [1- (m/n)]x = 2
Now divide both sides by [1- (m/n)]
2. You have set x equal to two different terms that are not the same. You may have copied the problem wrong. I will ignore the [2/x] - [2/(2x+1)] .
If x = 1/(x+1), then
x(x+1) = 1
x^2 + x -1 = 0
Use the quadratic equation for the two possible value of x. One is
x = [-1 + sqrt 5]/2
Now divide both sides by [1- (m/n)]
2. You have set x equal to two different terms that are not the same. You may have copied the problem wrong. I will ignore the [2/x] - [2/(2x+1)] .
If x = 1/(x+1), then
x(x+1) = 1
x^2 + x -1 = 0
Use the quadratic equation for the two possible value of x. One is
x = [-1 + sqrt 5]/2
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