Question
a 100 kg boulder is placed under the surface of water. its volume is 0.5 x 10^5 cm^3. what is the weight of the rock while under water; compare that to the weight of the rock in air (sitting on the ground)
i just found the weight of the rock in air by multiplying 100 kg by 9.8 and got 980 kg. but i don't know what to do next
i just found the weight of the rock in air by multiplying 100 kg by 9.8 and got 980 kg. but i don't know what to do next
Answers
bobpursley
No. The question is what is the weight of the rock as compared to in air.
The weight of the rock under water is
Wuw= mg-volume*densitywater*g
The weight of the rock in air is mg
comparing them..
wuw/Wair= (mg-volume*densitywater*g)/mg
= 1-volume*densitywater/m)
but m is volume*densityrock
Wuw/Wair= 1-densitywater/densityrock
check that math
The weight of the rock under water is
Wuw= mg-volume*densitywater*g
The weight of the rock in air is mg
comparing them..
wuw/Wair= (mg-volume*densitywater*g)/mg
= 1-volume*densitywater/m)
but m is volume*densityrock
Wuw/Wair= 1-densitywater/densityrock
check that math