Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point) Responses 10−30h=0 10 minus 30 h equals 0 1,280+30h=0 1,280 plus 30 h equals 0 1,280−30h=0 1,280 minus 30 h equals 0 30h=10

Answer 1

To find out how long the water in the cooler will last, we can set up an equation based on the information given.

We start with 1,280 ounces of water in the cooler (since 10 gallons is equal to 1,280 ounces). Each hour, 30 ounces of water are removed. If we let \( h \) represent the number of hours, the amount of water remaining in the cooler after \( h \) hours can be represented by the equation:

\[
1280 - 30h
\]

We want to find out when the water will run out, which means we set the equation equal to 0:

\[
1280 - 30h = 0
\]

So the correct equation showing how long the water in the cooler will last is:

\[
1280 - 30h = 0
\]

Thus, the correct response from the options is:

**1280−30h=0 (1,280 minus 30 h equals 0)**.