Question

Which correctly shows the area formula for a trapezoid, A=12h(b1+b2) , rearranged for the quantity of interest h?(1 point) Responses h=12A(b1+b2) h equals Start Fraction 1 over 2 End Fraction upper A left parenthesis b subscript 1 baseline plus b subscript 2 baseline right parenthesis b1=2Ah−b2 b subscript 1 baseline dequals Start Fraction 2 upper A over h End Fraction minus b subscript 2 baseline h=2Ab1+b2 h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction h=b1+b22A

Answer 1

To rearrange the area formula for a trapezoid \( A = \frac{1}{2}h(b_1 + b_2) \) for \( h \), follow these steps:

1. Start with the original formula: \[ A = \frac{1}{2}h(b_1 + b_2) \]

2. Multiply both sides by 2 to eliminate the fraction: \[ 2A = h(b_1 + b_2) \]

3. Now, divide both sides by \( (b_1 + b_2) \) to solve for \( h \): \[ h = \frac{2A}{b_1 + b_2} \]

Thus, the correct rearrangement for \( h \) is: \[ h = \frac{2A}{b_1 + b_2} \]

This corresponds to the response: h = Start Fraction 2 A over b subscript 1 baseline plus b subscript 2 baseline End Fraction.