To solve the compound inequality \( -2 \leq 2x + 13 - 4 < 1 \), we can break it down into two parts:
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Solve the left side: \[ -2 \leq 2x + 13 - 4 \] This simplifies to: \[ -2 \leq 2x + 9 \] Then, we isolate \( x \): \[ -2 - 9 \leq 2x \] \[ -11 \leq 2x \] Dividing both sides by 2 gives: \[ -\frac{11}{2} \leq x \] or \[ x \geq -\frac{11}{2} \]
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Solve the right side: \[ 2x + 13 - 4 < 1 \] This simplifies to: \[ 2x + 9 < 1 \] Isolate \( x \): \[ 2x < 1 - 9 \] \[ 2x < -8 \] Dividing both sides by 2 gives: \[ x < -4 \]
Now we can combine these two results:
The compound inequality is: \[ -\frac{11}{2} \leq x < -4 \]
In decimal form: \(-\frac{11}{2} = -5.5\).
This means we are looking for \( x \) values that satisfy: \[ -5.5 \leq x < -4 \]
Now let's match the resulting set to one of the provided options:
- {x: \(-\frac{3}{2} \leq x < 1\)} does not match our solution set.
- {x: \(3 \leq x < 7\)} does not match.
- {x: \(5/2 \leq x < 7\)} does not match.
- {x: \(-32 \leq x < 1\)} also does not match.
None of the given options correctly represent the solution \(-\frac{11}{2} \leq x < -4\). The correct representation isn't listed in the options provided.
Therefore, ensure to double check the inequality transformations and the final solutions before confirming the answer set against the provided options.