Asked by Jess
An advertisement claims that a particular automobile can "stop on a dime". What net force would actually be necessary to stop an automobile of mass 850Kg traveling initially at a speed of 43.0 km/h in a distance equal to the diameter of a dime, which is 1.8cm ?
Answers
Answered by
drwls
The "work against friction", F * X, would have to equal the initial kinetic evergy, (1/2) M V^2.
F = M V^2/(2 X)
Convert 43.0 km/h to ____m/s, X to 0.018 m, and solve for F in Newtons.
(1 Newton = 0.2248 pounds of force)
F = M V^2/(2 X)
Convert 43.0 km/h to ____m/s, X to 0.018 m, and solve for F in Newtons.
(1 Newton = 0.2248 pounds of force)
Answered by
jen
3493065
Answered by
Tshireletso
281916.7N
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