Use the information in the table to answer the question.

To find the total bond energy in the products of the reaction \( \text{H}_2 + \text{Cl}_2 \rightarrow 2 \text{HCl} \), we need to consider the bonds that are formed in the products.

In the products, we have 2 moles of \( \text{HCl} \). Since the bond energy for the \( \text{H–Cl} \) bond is 427 kJ/mol, the total bond energy for 2 moles of \( \text{HCl} \) can be calculated as follows:

\[
\text{Total bond energy} = 2 \times \text{Bond energy of H–Cl}
\]
\[
\text{Total bond energy} = 2 \times 427 \, \text{kJ/mol} = 854 \, \text{kJ/mol}
\]

Therefore, the total bond energy in the products of the reaction is **854 kJ/mol**.