Question

Use the information in the table to answer the question.

Bond Bond Energy (kJ/mol)
H-I 297
H-H 435
I-I 151
Hydrogen and iodine gases react to produce hydroiodic acid according to the reaction.

H2+I2→2HI

How much total bond energy in kJ/mol is in the products of the reaction?

(1 point)
Responses

448
448

594
594

453
453

297
297
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Answer 1

To calculate the total bond energy in the products of the reaction \( H_2 + I_2 \rightarrow 2 HI \), we will consider the bond energies of the hydroiodic acid (HI) produced.

Since the reaction produces 2 moles of HI, we need to take into account the bond energy of 1 mole of HI and then multiply it by 2.

Given the bond energy of HI is 297 kJ/mol, the total bond energy for the products is:

\[
\text{Total bond energy} = 2 \times \text{Bond energy of HI}
\]
\[
= 2 \times 297 \text{ kJ/mol}
\]
\[
= 594 \text{ kJ/mol}
\]

Therefore, the total bond energy in the products of the reaction is **594 kJ/mol**.