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Original Question
Initially sliding with a speed of 2.3 m/s, a 2.0 kg block collides with a spring and compresses it 0.41 m before coming to rest...Asked by Helen Batt
Initially sliding with a speed of 2.1 m/s, a 2.1 kg block collides with a spring and compresses it 0.35 m before coming to rest. What is the force constant of the spring?
Answers
Answered by
bobpursley
InitialKE= 1/2 m v^2
1/2 kx^2= KE=1/2 mv^2
k= mv^2/x^2
1/2 kx^2= KE=1/2 mv^2
k= mv^2/x^2
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