Question

Solve the system of equations.
–9x+y=12

2x+4y= −28
(1 point)
(
,
)

Answer 1

To solve the system of equations:

1. \(-9x + y = 12\)
2. \(2x + 4y = -28\)

We can solve one of the equations for one variable and then substitute it into the other equation.

Let's start with the first equation:

\[
y = 9x + 12
\]

Now, we will substitute \(y\) in the second equation:

\[
2x + 4(9x + 12) = -28
\]

Now, distribute the \(4\):

\[
2x + 36x + 48 = -28
\]

Combine like terms:

\[
38x + 48 = -28
\]

Now, subtract \(48\) from both sides:

\[
38x = -28 - 48
\]
\[
38x = -76
\]

Now, divide by \(38\):

\[
x = \frac{-76}{38} = -2
\]

Now that we have \(x\), we substitute it back to find \(y\):

\[
y = 9(-2) + 12
\]
\[
y = -18 + 12
\]
\[
y = -6
\]

So the solution to the system of equations is:

\[
\boxed{(-2, -6)}
\]