Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
During the process of Photosystem I, NADP+ is changed into NADPH . NADPH has a neutral charge. What reactants are necessary to...Question
During the process of Photosystem I, NADP+ is changed into NADPH. NADPH has a neutral charge. What reactants are necessary to form the product?(1 point)
Responses
an electron and a hydrogen ion
an electron and a hydrogen ion
two electrons and two hydrogen ions
two electrons and two hydrogen ions
two electrons and a hydrogen ion
two electrons and a hydrogen ion
an electron and two hydrogen ions
Responses
an electron and a hydrogen ion
an electron and a hydrogen ion
two electrons and two hydrogen ions
two electrons and two hydrogen ions
two electrons and a hydrogen ion
two electrons and a hydrogen ion
an electron and two hydrogen ions
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The correct response is:
**two electrons and a hydrogen ion.**
In the process of Photosystem I, NADP+ is reduced to NADPH, which requires two electrons and one hydrogen ion (H⁺) to complete the reduction process. The overall reaction can be summarized as:
\[ \text{NADP}^+ + 2e^- + H^+ \rightarrow \text{NADPH} \]
This indicates that two electrons and one hydrogen ion are involved in the formation of NADPH from NADP+.
**two electrons and a hydrogen ion.**
In the process of Photosystem I, NADP+ is reduced to NADPH, which requires two electrons and one hydrogen ion (H⁺) to complete the reduction process. The overall reaction can be summarized as:
\[ \text{NADP}^+ + 2e^- + H^+ \rightarrow \text{NADPH} \]
This indicates that two electrons and one hydrogen ion are involved in the formation of NADPH from NADP+.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.