Asked by Jematormal91
Consider a process in which an ideal gas is compressed to one-sixth of its original volume at constant temperature. Calculate the entropy change per mole of gas.
I know that the formula is chg.entropy= nRln(V2/V1), but how do I get the values for V2 and V1?
I know that the formula is chg.entropy= nRln(V2/V1), but how do I get the values for V2 and V1?
Answers
Answered by
DrBob222
You do one of two things.
1. V1 = V1; then V2 = 1/6 V1 OR
2. make up a volume for V1 (a convenient number like 600 mL; then V2 = 100.
It doesn't matter which way you do it, V2/V1 = 1/6
1. V1 = V1; then V2 = 1/6 V1 OR
2. make up a volume for V1 (a convenient number like 600 mL; then V2 = 100.
It doesn't matter which way you do it, V2/V1 = 1/6
Answered by
DrBob222
I didn't address how you get n and R. I don't see enough information for n. Perhaps there is more to the problem.
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