To solve for $ k $ in the equation $ c = \frac{1}{2}kv $, we can follow these steps: 1. Start with the original equation: \[ c = \frac{1}{2}kv \] 2. Multiply both sides of the equation by 2 to eliminate the fraction: \[ 2c = kv \] 3. Now, divide both sides by $ v $ to isolate $ k $: \[ k = \frac{2c}{v} \] Thus, the solution for $ k $ is: \[ k = \frac{2c}{v} \]

To solve for $ h $ in the equation $ q = 5h + 5v $, follow these steps: 1. Start with the original equation: \[ q = 5h + 5v \] 2. Subtract $ 5v $ from both sides to isolate the term with $ h $: \[ q - 5v = 5h \] 3. Now, divide both sides by 5 to solve for $ h $: \[ h = \frac{q - 5v}{5} \] Thus, the solution for $ h $ is: \[ h = \frac{q - 5v}{5} \]