To solve for \( k \) in the equation \( c = \frac{1}{2}kv \), we can follow these steps: 1. Start with the original equation: \[ c = \frac{1}{2}kv \] 2. Multiply both sides of the equation by 2 to eliminate the fraction: \[ 2c = kv \] 3. Now, divide both sides by \( v \) to isolate \( k \): \[ k = \frac{2c}{v} \] Thus, the solution for \( k \) is: \[ k = \frac{2c}{v} \]

To solve for \( h \) in the equation \( q = 5h + 5v \), follow these steps: 1. Start with the original equation: \[ q = 5h + 5v \] 2. Subtract \( 5v \) from both sides to isolate the term with \( h \): \[ q - 5v = 5h \] 3. Now, divide both sides by 5 to solve for \( h \): \[ h = \frac{q - 5v}{5} \] Thus, the solution for \( h \) is: \[ h = \frac{q - 5v}{5} \]

Solve for k. c=1/2kv

To solve for \( k \) in the equation \( c = \frac{1}{2}kv \), we can follow these steps:

Start with the original equation: \[ c = \frac{1}{2}kv \]
Multiply both sides of the equation by 2 to eliminate the fraction: \[ 2c = kv \]
Now, divide both sides by \( v \) to isolate \( k \): \[ k = \frac{2c}{v} \]

Thus, the solution for \( k \) is: \[ k = \frac{2c}{v} \]

Solve for h.
q=5h+5v

To solve for \( h \) in the equation \( q = 5h + 5v \), follow these steps:

Start with the original equation: \[ q = 5h + 5v \]
Subtract \( 5v \) from both sides to isolate the term with \( h \): \[ q - 5v = 5h \]
Now, divide both sides by 5 to solve for \( h \): \[ h = \frac{q - 5v}{5} \]

Thus, the solution for \( h \) is: \[ h = \frac{q - 5v}{5} \]