Ammonia is a weak base. Potassium hydroxide is a strong base. Which statement is correct?(1 point)

Responses

A solution of potassium hydroxide will always have a lesser concentration of solute than a solution of ammonia.
A solution of potassium hydroxide will always have a lesser concentration of solute than a solution of ammonia.

A solution of potassium hydroxide will always have more OH– ions than a solution of ammonia.
A solution of potassium hydroxide will always have more OH– ions than a solution of ammonia.

A solution of potassium hydroxide will always have lesser conductivity than a solution of ammonia.
A solution of potassium hydroxide will always have lesser conductivity than a solution of ammonia.

A solution of potassium hydroxide will always have a lower pH than a solution of ammonia.

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 month ago

The correct statement is:

**A solution of potassium hydroxide will always have more OH– ions than a solution of ammonia.**

Here's the reasoning:

1. **Potassium hydroxide (KOH)** is a strong base and fully dissociates in solution to produce a higher concentration of hydroxide ions (OH–) compared to ammonia.
2. **Ammonia (NH3)** is a weak base and only partially dissociates to produce hydroxide ions, resulting in a significantly lower concentration of OH– ions compared to a strong base like KOH.
3. Because of this complete dissociation of KOH and the incomplete dissociation of NH3, a solution of KOH will always contain more OH– ions than a solution of ammonia.

The other statements are incorrect because:

- The concentration of solute can vary; KOH solutions can have lower concentrations than ammonia solutions depending on how they are prepared.
- The conductivity of a solution is related to the concentration of ions. A KOH solution would typically have higher conductivity due to more available ions.
- The pH of a KOH solution will be higher than that of an ammonia solution because KOH is a stronger base.