A certain weak base has a Kb of 8.10 × 10-7. What concentration of this base will produce a pH of 10.00?

Answer 1

pH = 10; pOH = 4; (OH^-) = 1E-4
.............BOH ==> B^+ + OH^-
initial.......x......0......0
equil.......x-1E-4...1E-4..1E-4
Kb = (B^+)(OH^-)/(BOH)