In an isosceles triangle, the vertex angle is 28 degrees. What are the measures of each of the base angles?(1 point)

In an isosceles triangle, the two base angles are equal. The sum of all angles in a triangle is always 180 degrees.

Given that the vertex angle is 28 degrees, we can calculate the base angles as follows:

1. Subtract the vertex angle from 180 degrees:
\[
180^\circ - 28^\circ = 152^\circ
\]

2. Since the two base angles are equal, divide the remaining angle (152 degrees) by 2:
\[
\frac{152^\circ}{2} = 76^\circ
\]

Thus, each of the base angles measures **76 degrees**.