Asked by vikram
Triangle PQR is an isosceles triangle. The side QP is produced to S. Such tha PQ=PS,prove tha angle QRS=90 degree.
Answers
Answered by
Steve
You have not said, but this only works if P is the vertex between the equal sides.
So, let the base be 2b and each of the two equal sides be s.
Then the altitude is h and
b^2+h^2 = s^2
That is, if the midpoint of the base is M, then
QM^2 + PM^2 = PQ^2
Now, if PQ=PS, S is the midpoint of QP and M is the midpoint of QR
That means that ∆QMP ~ ∆QRS and since ∆QMP is a right triangle, so is ∆QRS, making R a right angle.
So, let the base be 2b and each of the two equal sides be s.
Then the altitude is h and
b^2+h^2 = s^2
That is, if the midpoint of the base is M, then
QM^2 + PM^2 = PQ^2
Now, if PQ=PS, S is the midpoint of QP and M is the midpoint of QR
That means that ∆QMP ~ ∆QRS and since ∆QMP is a right triangle, so is ∆QRS, making R a right angle.
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