m(1/2)[V2^2 - V1^2] = m a X
(from energy and work considerations)
Cancel the m's
[V2^2 - V1^2] = 2 a X = -75 m^2/s^2
Solve for a, which will be negative in this case.
X = 50 m
V1 and V2 are the initial and final speeds (measured positive down)
a = -0.75 m/s^2
The speed of a rain is reduced unformly from 10m/s to 5m/s while covering a distance of 50m.What is its acceleration??
1 answer