Asked by Anonymous
the speed of a train is reduced uniformly from 10 m/s to 5 m/s while covering a distance of 150 m. What is the acceleration of the train? how much farther will it travel before coming to rest, assuming the same acceleration ?
Answers
Answered by
Henry
Vo = 10 m/s.
V = 5 m/s.
d = 150 m.
a = ?
a. V^2 = Vo^2 + 2a*d
a = (V^2-Vo^2)/2d =
b. d = (V^2-Vo^2)/2a. V = 0, Vo = 5 m/s.
V = 5 m/s.
d = 150 m.
a = ?
a. V^2 = Vo^2 + 2a*d
a = (V^2-Vo^2)/2d =
b. d = (V^2-Vo^2)/2a. V = 0, Vo = 5 m/s.
Answered by
gfdxgvdfgv
gfhfghb
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.