Asked by Abbey
Complete the identity
secQ - 1/secQ =
secQ Is this correct?
secQ - 1/secQ =
secQ Is this correct?
Answers
Answered by
FredR
It doesn't look right to me
sec Q - 1/sec Q =
1/cos - cos =
1/cos - cos^2/cos =
(1-cos^2)/cos =
sin^2/cos
sec Q - 1/sec Q =
1/cos - cos =
1/cos - cos^2/cos =
(1-cos^2)/cos =
sin^2/cos
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