Asked by Alex
Show that the equation
log y = 1.54 - .008x - .658 log x
is equivalent to
y = 34.7 (1.0186)^(-x) * x^(-.658)
log y = 1.54 - .008x - .658 log x
is equivalent to
y = 34.7 (1.0186)^(-x) * x^(-.658)
Answers
Answered by
bobpursley
take the antilog of each side
y= 10^(1.54-.008x-.658logx)
y= 10^1.54 * 10^-(.008*x) * x^.658
= 34.7((10^.008)^-x)*x^.658
you can take it from here.
remember log a+logb = log ab
and a^xy= (a^x)^y
y= 10^(1.54-.008x-.658logx)
y= 10^1.54 * 10^-(.008*x) * x^.658
= 34.7((10^.008)^-x)*x^.658
you can take it from here.
remember log a+logb = log ab
and a^xy= (a^x)^y
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