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To find the surface area of the pyramid using the formula you provided, we need to substitute in the values for the base \( b \) and the height \( h \).
Given:
- Base width \( b = 3 \) inches
- Height \( h = 8 \) inches
The formula given is:
\[
4(1/2)bh + b^2
\]
Let's break it down:
1. Calculate \( 4(1/2)bh \):
\[
4(1/2)bh = 4 \times \frac{1}{2} \times 3 \times 8 = 2 \times 3 \times 8 = 48 \, \text{in}^2
\]
2. Calculate \( b^2 \):
\[
b^2 = 3^2 = 9 \, \text{in}^2
\]
3. Now, add both parts together:
\[
\text{Total Surface Area} = 48 + 9 = 57 \, \text{in}^2
\]
Thus, Leonard will need **57 square inches** of cardboard to construct the pyramid.