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Leonard is going to construct a pyramid with cardboard for math class. Find how many square inches (in.2) of cardboard he will...Asked by i love tristen<3
Leonard is going to construct a pyramid with cardboard for math class. Find how many square inches (in.2)
of cardboard he will need. Use 4(12)bh+b2
, where b
, the base of the pyramid, is 3 in. and h
, the height of the pyramid, is 8 in.(1 point)
of cardboard he will need. Use 4(12)bh+b2
, where b
, the base of the pyramid, is 3 in. and h
, the height of the pyramid, is 8 in.(1 point)
Answers
Answered by
GPT-4o mini
To find the amount of cardboard Leonard will need to construct the pyramid, we can use the formula provided:
\[
\text{Surface Area} = 4(12)bh + b^2
\]
where:
- \( b \) is the base length of the pyramid, which is 3 inches,
- \( h \) is the height of the pyramid, which is 8 inches.
Let's substitute \( b = 3 \) and \( h = 8 \) into the formula:
First, calculate \( b^2 \):
\[
b^2 = 3^2 = 9
\]
Next, calculate \( 4(12)bh \):
\[
4(12)bh = 4(12)(3)(8)
\]
Now calculating step-by-step:
1. Calculate \( 3 \times 8 = 24 \).
2. Then, calculate \( 12 \times 24 = 288 \).
3. Finally, calculate \( 4 \times 288 = 1152 \).
Now, put it all together:
\[
\text{Surface Area} = 1152 + 9 = 1161
\]
So, the total area of cardboard Leonard will need to construct the pyramid is **1161 square inches**.
\[
\text{Surface Area} = 4(12)bh + b^2
\]
where:
- \( b \) is the base length of the pyramid, which is 3 inches,
- \( h \) is the height of the pyramid, which is 8 inches.
Let's substitute \( b = 3 \) and \( h = 8 \) into the formula:
First, calculate \( b^2 \):
\[
b^2 = 3^2 = 9
\]
Next, calculate \( 4(12)bh \):
\[
4(12)bh = 4(12)(3)(8)
\]
Now calculating step-by-step:
1. Calculate \( 3 \times 8 = 24 \).
2. Then, calculate \( 12 \times 24 = 288 \).
3. Finally, calculate \( 4 \times 288 = 1152 \).
Now, put it all together:
\[
\text{Surface Area} = 1152 + 9 = 1161
\]
So, the total area of cardboard Leonard will need to construct the pyramid is **1161 square inches**.
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