Asked by CC
The molarity of urea in a solution prepared by dissolving 16 g of urea (MW 60.0g/mol) in 39 g of H2O is ______M. The density of the solution is 1.3 g/ml.
Answers
Answered by
FredR
Moles of solute = 16 g / 60 g/M =
= 0.267 M
volume of H2O = 39g/1.3 g/ml = 30 ml
= 0.03 l
molarity = 0.267 M / 0.03 l
= 8.89 M/l
= 0.267 M
volume of H2O = 39g/1.3 g/ml = 30 ml
= 0.03 l
molarity = 0.267 M / 0.03 l
= 8.89 M/l
Answered by
Smarty Pants
you have you add the total grams. so its 16g+39g=55g. so 55g/1.3g/ml=0.0421 L
0.267/.0421=6.3 M
0.267/.0421=6.3 M