Asked by Anonymous

What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450.0 mL solution?
Answered by Dr. Jane
Molarity is moles/liter

8 grams/molecular weight of BaCl2

You will have moles in /450 = ?? moles/1000
Answered by Mayank Mishra
Molarity =moles of solute /volume of soln in let.
Moles of BaCl2=given mass /molecular mass
=8/80=1/10 =0.1moles.
Now,
M=0.1/0.45=10/45=2/9 =0.222molar.
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