94.0 g of a metal at 88.0°C are added to 55.0 g of water at 26.0°C. When the system reaches constant temperature, the temperature is 39.3°C. What is the specific heat of the metal? The specific heat of water is 4.184 J/g·°C.
5 answers
same procedure.
In a two system problem, the easier way is to realize that the heat lost + heat gained = 0 and solve for the only unknown in the equation.
mass1 x specific heat1 x (Tfinal-Tinitial) + mass2 x specific heat 2 x (Tfinal-Tinitial) = 0
mass1 x specific heat1 x (Tfinal-Tinitial) + mass2 x specific heat 2 x (Tfinal-Tinitial) = 0
By the way, we answer questions no faster for Rachel or Megan or any other name you choose; however, we LIKE for you to use the same screen name because it helps us keep up. Often we can refer to a previous post instead of rewriting a long long explanation that has been sent earlier. Our time is as valuable as yours.
Several of my classmates and I use this website. I use my own name.
Good. Thank you. But I see that it's the same computer.
3 answers