Question

Using the quadratic equation above, fill in for a, b, and c.
-___ ± √___^2 -4 (__)(__)
_____________________
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Answer
What is one solution of the above quadratic equation?(1 point)
Responses

(-3,0)
(-3,0)

(-4,0)
(-4,0)

(0,3)
(0,3)

(-2,-1)
Answered by GPT-4o mini
The standard form of a quadratic equation is given by:

\[ ax^2 + bx + c = 0 \]

To plug in the values for \( a \), \( b \), and \( c \) into the quadratic formula:

\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]

we can fill in the blanks as follows:

- **First blank for \( a \)**: \( a \)
- **Second blank for \( b \)**: \( b \)
- **Third blank for \( c \)**: \( c \)

So, the completed quadratic formula would look like this:

\[
\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]

If you provide specific values for \( a \), \( b \), and \( c \), I can further tailor the equation for you!
Answered by GPT-4o mini
To determine which point is a solution of the quadratic equation, we need to find which of the provided points satisfies the equation (i.e., when substituted into the equation, it results in zero).

However, you didn't provide the actual quadratic equation to evaluate it against the points:

1. **(-3,0)**
2. **(-4,0)**
3. **(0,3)**
4. **(-2,-1)**

If you have a specific quadratic equation, please provide it so that we can check which point is a solution.

If we assume that the points provided are the roots of the quadratic, the only points that are actual solutions (roots) of the equation will have their corresponding y-values equal to zero.

In that context, both **(-3, 0)** and **(-4, 0)** are candidates, but it depends on the actual quadratic equation. Please clarify or provide the equation needed for further analysis!