aksed find the equation oft he parabola y=ax^2 + bx +c. there are four given clues
1) the y-intercept is (0,6)
2) the curve goes throuth (4,5)
3) the curve has aturning point at (2,3)
4) the line of symmetry is x=1
a)is it not possible for all four clues to be true together (why not?)
b)which combinations of clues enable you to find a set of values a,b and c?
c)find the resulting parabola for each successful combination
2 answers
7+4+5-3+9-10+7-8
(a) If the curve has a "turning point" (minimum or maximum) at (2,3), its line of symmetry would have to be x=2.