Question

Nitrogen and hydrogen react to form ammonia. Consider the mixture of N2 and H2 in a closed container as illustrated below.

The container contains 6 hydrogen atoms and 6 nitrogen atoms (all diatomic)

Assuming the reaction goes to completion, draw a representation of the product mixture. Explain how you arrived at this representation.

Answer 1

You couldn't draw the picture in your "illustrated below" example and neither can I.
You must have something like this/
H-H ......N-N
H-H ......N-N
H-H.......N-N

That's 6 H atoms and 6 N atoms. I would draw a circle around ONE of the top N atoms, two of the top H atoms and one H of the second row showing 1 NH3 was formed. Then I would do the same kind of thing for the top N on the right, the one H on the second row and both H atoms on the third row. That represents another NH3 formed. That leaves 4 N atoms un-reacted, 2 NH3 molecules formed, and no atoms H remaining.
That makes sense when you consider the equation is N2 + 3H2 ==> 2NH3 doesn't it>

Answer 2

This would form two NH3 molecules, and leave 5 N2 pairs.
It would be:
NH3
N2 N2 N2 N2 N2
NH3