To identify the combination of molecules that will produce ammonia (NH3) with no leftovers, we need to look at the balanced equation for its formation from nitrogen (N2) and hydrogen (H2):
\[ N_2 + 3H_2 \rightarrow 2NH_3 \]
From the equation, we see that:
- 1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2) to produce 2 moles of ammonia (NH3).
To find a combination that produces ammonia with no leftovers, we can use the stoichiometry of the balanced equation. Let's analyze some specific mole combinations:
- For every 1 mole of N2, you need exactly 3 moles of H2.
If we have:
- 1 mole of N2
- 3 moles of H2
This will produce:
- 2 moles of NH3
There will be no leftover of N2 or H2 as they are fully consumed in this reaction.
If you were to provide any other combinations (like 2 moles of N2 or less than 3 moles of H2), you would either have leftover reactants or not enough to produce ammonia fully.
In conclusion, the combination that produces ammonia (NH3) with no leftover is:
1 mole of N2 and 3 moles of H2.
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