It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula:

Question

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

8N2 and 4H2
8 n sub 2 and 4 h sub 2

2N2 and 6H2
2 n sub 2 and 6 h sub 2

4N2 and 4H2
4 n sub 2 and 4 h sub 2

5N2 and 6H2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we first need to analyze the stoichiometry of the reaction:

1 N₂ + 3 H₂ → 2 NH₃

From this reaction, we can see that:

• 1 molecule of N₂ requires 3 molecules of H₂ to produce 2 molecules of NH₃.

Now, let's evaluate each option to see which one meets the requirement of producing ammonia with no leftovers.

1. 8 N₂ and 4 H₂:

   • For 8 N₂, the required H₂ would be: 8 * 3 = 24 H₂.
   • Here we have only 4 H₂, which is not enough.

2. 2 N₂ and 6 H₂:

   • For 2 N₂, the required H₂ would be: 2 * 3 = 6 H₂.
   • This matches perfectly.
   • Produced NH₃ = 2 N₂ → 2 * 2 = 4 NH₃ (no leftovers).

3. 4 N₂ and 4 H₂:

   • For 4 N₂, the required H₂ would be: 4 * 3 = 12 H₂.
   • Here we only have 4 H₂, which is not enough.

4. 5 N₂ and 6 H₂:

   • For 5 N₂, the required H₂ would be: 5 * 3 = 15 H₂.
   • Here we have only 6 H₂, which is not enough.

Evaluating the options, the only combination that produces ammonia with no leftovers is:

2 N₂ and 6 H₂.