To find out how much water is contained in the tank when it is \( \frac{8}{15} \) full, we first need to calculate \( \frac{8}{15} \) of the total capacity of the tank.
The total capacity of the tank is \( 561/4 \) litres. First, let's convert this mixed fraction into an improper fraction:
\[ 561/4 = 561 \div 4 = 140.25 \text{ litres} \]
Now, multiply this amount by \( \frac{8}{15} \):
\[ \text{Water contained} = \frac{8}{15} \times \frac{561}{4} \]
We can simplify this step by step:
- Multiply the fractions:
\[ = \frac{8 \times 561}{15 \times 4} \]
Calculating the numerator:
\[ 8 \times 561 = 4488 \]
Calculating the denominator:
\[ 15 \times 4 = 60 \]
So we have:
\[ \text{Water contained} = \frac{4488}{60} \]
Now, simplify \( \frac{4488}{60} \):
Calculating \( 4488 \div 60 \):
Perform the division.
\[ 4488 \div 60 = 74.8 \text{ litres} \]
Therefore, the amount of water contained in the tank when it is \( \frac{8}{15} \) full is \( 74.8 \) litres.
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